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-x^2+110x-1200=0
We add all the numbers together, and all the variables
-1x^2+110x-1200=0
a = -1; b = 110; c = -1200;
Δ = b2-4ac
Δ = 1102-4·(-1)·(-1200)
Δ = 7300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7300}=\sqrt{100*73}=\sqrt{100}*\sqrt{73}=10\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-10\sqrt{73}}{2*-1}=\frac{-110-10\sqrt{73}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+10\sqrt{73}}{2*-1}=\frac{-110+10\sqrt{73}}{-2} $
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